Vietnamese original player learns the Top 10 star in the world in the ATP 500


The Vietnamese -based Vietnamese player has just created a “earthquake” when he excelled over the famous opponent Andrey Rubleev in the second round of the Washington Expansion 2025.

Tien 5 times to encounter rivals in the top 10 this year

Learner Tien is going through extremely successful phase. In 5 times encountering rivals in the top 10 this year, he won 4 victories against Daniil Medvedev (Australia), Alexander Zverev (Acapulco), Ben Shelton (Mallorca) and the latest Rubleev (Washington).

In the last match, Learner Tien had a lot of difficulties before RubleV. In the first set, he faced 3 set-point in game 10, but finally won with a score of 7-5.

In the second set, the Russian tennis player with the mentality of unstable loses in the first game despite being serve. Knowing the advantage in hand, the more learned the better, while Rubleev missed a lot of unfortunate scores. As a result, RubleV continued to lose with a score of 2-6, so he had to give tickets to the opponent.

Rubleev lost money in both sets

Defeating RubleV, Learner Tien will clash the 12th seed Alejandro Davidovich Fokina. If this obstacle continues, American player will become a rival of the number one variety Taylor Fritz in the quarterfinals.

Learner Tien was born on December 2, 2005 in the US, with parents who are Vietnamese. Since starting a business up to now, he has won 3 Challenger titles, four times in Grand Slam and once reached the quarterfinals of ATP 250. In the three previous Grand Slam tournaments (the US expanded 2022, 2023 and 2024), Learner Tien soon had to stop right from the first round.

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